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the_mcanuff_stuff Caterham 14 Mar 16 1.05pm | |
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Originally posted by Stuk
As it's the only way to work out everything. Otherwise it's a question with 8 answers. OK, I get it. Still 2 or more possible solutions following the second clue, meaning there must be 2 or more solutions, i.e. the sum must be 13. so 1,6,6, or 2,2,9 so it must be 1,6,6, again assuming that 2,2,9 can't have a youngest. Which is bollocks, as I'm a twin and I'm younger by a minute. As my twin delights in reminding me.
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Stuk Top half 14 Mar 16 1.23pm | |
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Originally posted by the_mcanuff_stuff
OK, I get it. Still 2 or more possible solutions following the second clue, meaning there must be 2 or more solutions, i.e. the sum must be 13. so 1,6,6, or 2,2,9 so it must be 1,6,6, again assuming that 2,2,9 can't have a youngest. Which is bollocks, as I'm a twin and I'm younger by a minute. As my twin delights in reminding me. Yes, that's been extensively covered. Where is this pig problem?
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the_mcanuff_stuff Caterham 14 Mar 16 1.26pm | |
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Originally posted by mr. apollo
Question from a Year 9 (!) maths paper...
Edited by mr. apollo (11 Mar 2016 3.55pm) So this is confusing me. You have 4 stys arranged around you and you circle them and every time you get nearer to 10? And it's not averages. I don't see how it could work. If it was the final sty closer to 10, that is easy (and has many solutions). Any clue as to a factor I'm not considering? Edited by the_mcanuff_stuff (14 Mar 2016 1.30pm)
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the_mcanuff_stuff Caterham 14 Mar 16 1.27pm | |
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Yeah, sorry, I'm being a bit slow today. Pig problem - original post. And I just replied to it.
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the_mcanuff_stuff Caterham 14 Mar 16 1.39pm | |
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Originally posted by the_mcanuff_stuff
So this is confusing me. You have 4 stys arranged around you and you circle them and every time you get nearer to 10? And it's not averages. I don't see how it could work. If it was the final sty closer to 10, that is easy (and has many solutions). Any clue as to a factor I'm not considering? Edited by the_mcanuff_stuff (14 Mar 2016 1.30pm) So here is my problem. I'll arrange the pigs as: 0,19,2,3 great, every pen I go to gets closer to 10, until I go round again. My final pen is 7 "off" the target value and the first goes back to being 10 off the target value and surely that will never change?
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Stuk Top half 14 Mar 16 1.47pm | |
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Originally posted by the_mcanuff_stuff
So here is my problem. I'll arrange the pigs as: 0,19,2,3 great, every pen I go to gets closer to 10, until I go round again. My final pen is 7 "off" the target value and the first goes back to being 10 off the target value and surely that will never change? This isn't a mathematical problem I reckon. As you've already said, it would not be possible.
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DanH SW2 14 Mar 16 1.59pm | |
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Only just read this thread. Classic stuff.
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mr. apollo Somewhere in Switzerland 14 Mar 16 2.02pm | |
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Originally posted by Stuk
This isn't a mathematical problem I reckon. As you've already said, it would not be possible.
Edited by mr. apollo (14 Mar 2016 2.03pm)
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the_mcanuff_stuff Caterham 14 Mar 16 2.47pm | |
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Originally posted by mr. apollo
Edited by mr. apollo (14 Mar 2016 2.03pm) Ah, so this is a maths problem, but an abstract one. I'll continue to wrack my brain. But in the meantime I need to get on with work
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DanH SW2 14 Mar 16 2.58pm | |
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Originally posted by mr. apollo
Question from a Year 9 (!) maths paper...
Edited by mr. apollo (11 Mar 2016 3.55pm) 3, 4, 8 and 9?
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Stuk Top half 14 Mar 16 3.24pm | |
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How would 3 be closer to 10 than 9? Definitely not a numerical/maths only answer.
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DanH SW2 14 Mar 16 3.39pm | |
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Originally posted by Stuk
How would 3 be closer to 10 than 9? Definitely not a numerical/maths only answer.
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